linear algebra? like y=mx+c? how hard could it be
linear algebra? like y=mx+c? how hard could it be
there's probably something I'm missing but isn't it y=mx+b?
i use c because i use c when integrating. (because if you integrate a constant and get a line, 'C’ being the constant of integration naturally becomes the y-intercept)
These were jeffalo’s last words. Immediately after saying this, a zero matrix snuck up behind him while he wasn’t looking and attacked.
Let it be known I do not like when they try to use y=a+bx